At my casino ( Won't tell where but its in the eastern United states) there is a bonus game where if you put in an extra 1 dollar bet you can win the following if you are dealt:
1 ace=3 dollars
2 aces=15 dollars
2 suited aces=50 dollars
3 aces=200 dollars
3 aces suited=2000 dollars
4 aces=2000
4 aces red or black=jackpot
The one ace has to be on your first card though and the two aces have to be back to back. Now normally you would never take that bet because of the odds.
(1/13) times 3$ = .2301$
(1/169) times 15$ =.0888$
(1/2704) times 50$ =.0185 $
(1/2197) times 200$=.091$
etc etc.
Now I calculated to make money you need about 6-7 aces in the deck for it to be worth your money. Is there any point side counting aces for this purpose?
1 ace=3 dollars
2 aces=15 dollars
2 suited aces=50 dollars
3 aces=200 dollars
3 aces suited=2000 dollars
4 aces=2000
4 aces red or black=jackpot
The one ace has to be on your first card though and the two aces have to be back to back. Now normally you would never take that bet because of the odds.
(1/13) times 3$ = .2301$
(1/169) times 15$ =.0888$
(1/2704) times 50$ =.0185 $
(1/2197) times 200$=.091$
etc etc.
Now I calculated to make money you need about 6-7 aces in the deck for it to be worth your money. Is there any point side counting aces for this purpose?