shadroch said:
Snyder says the majority of your money comes from suited pairs, which is why he says play only the game that pays 3-1 on them. I'm curious how many non- KQs must be out of play before the bet becomes EV positive in the 2 1/2 and 25 payout mode.
EV = (Probability of Lose)(Wager) + (Probability of Suited hand not K,Q)(2.5 x wager) + (Probability of Suited K,Q)(25 x wager)
Well, for the above equation if you set EV = 0 (break-even situation) and rearrange it so that it is in terms of (Probability of Suited K,Q), then you can solve for what the probability of getting suited K,Q needs to be for the bet to be break-even. Of course, you'd make the simplifying assumption that the probability of getting a suited hand (not K,Q) is always the same as off the top of the shoe.
Once you have found what the probability of getting suited K,Q needs to be in order for the bet to be break-even, then you can compute what percentage of the remaining decks need to be K's and Q's (assuming there is a normal suit distribution) for the bet to be break-even.
Perhaps I might have time this weekend to work this out if someone else (or you) don't get to it first.
Spaw