I got a request to help calculate the insurance index for the game without 10's (you know which one!) so I figure I would post the results here. If the requester wishes to be known, he/she can speak up here!
Okay, here it goes. All my methodology is based on http://www.blackjackforumonline.com/content/AlgebraicIndices.htm
Firstly, the insurance EV off the top is:
EV_Top = 12/48 * 2 + 36/48 * -1 = -1/4
Then, we want the EOR for a given card. So let's remove a non-ten.
EV = 12/47 * 2 + 35/47 * -1 = -11/47
EOR_NonTen = -11/47 - (-1/4) = 3/188
The EOR of a ten is:
EV = 11/47 * 2 + 36/47 * -1 = -14/47
EOR_Ten = -14/47 - (-1/4) = -9/188
As a proof of concept, let's make sure the EOR = 0 for a full 48-card deck:
36 * 3/188 + 12 * -9/188 = 0
Next, we will use a simple ace-neutral count with 2,7,8,A as 0, 3-6 as +1, and 9-X as -1 in an 8-deck shoe (384 cards).
Since the Aces aren't counted, we don't need to rebalance the tags after we remove an Ace (read the website above). For Ace-reckoned counts, it becomes a bit more complicated, but easily do-able.
The equation from the website requires the sum of squared tags (y) for the entire shoe, which yields y = 127 * 0 + 128 * (1)^2 + 128 * (-1)^2 = 256. So we have TC * (+/- 1) * 383/256 for each card. This would be different if the tags had to be rebalanced.
We can then combine all the EV's to determine the overall insurance EV at a given count:
EV =
-1/4 + <-- Off the top
3/188 * 47/383 + <-- Dealer's Ace upcard
127 * TC * 0 + <-- 2,7,8,A are 0 since they aren't rebalanced
128 * TC * 383/256 * 3/188 * 47/383 + <-- 3 through 6
32 * TC * -383/256 * 3/188 * 47/383 + <-- 9
96 * TC * -383/256 * -9/188 * 47/383 <-- Faces
Simplifying:
EV = 9/8 * TC - 95/383
Setting EV to 0, we get:
9/8 * TC = 95/383
TC = 760 / 3447
Then, we use the equation in the website above to get the index:
Index = (760 / 3447 - 1/383) * 48 = 12061/1149 = 10.46
So when the TC > +11, take insurance.
Okay, here it goes. All my methodology is based on http://www.blackjackforumonline.com/content/AlgebraicIndices.htm
Firstly, the insurance EV off the top is:
EV_Top = 12/48 * 2 + 36/48 * -1 = -1/4
Then, we want the EOR for a given card. So let's remove a non-ten.
EV = 12/47 * 2 + 35/47 * -1 = -11/47
EOR_NonTen = -11/47 - (-1/4) = 3/188
The EOR of a ten is:
EV = 11/47 * 2 + 36/47 * -1 = -14/47
EOR_Ten = -14/47 - (-1/4) = -9/188
As a proof of concept, let's make sure the EOR = 0 for a full 48-card deck:
36 * 3/188 + 12 * -9/188 = 0
Next, we will use a simple ace-neutral count with 2,7,8,A as 0, 3-6 as +1, and 9-X as -1 in an 8-deck shoe (384 cards).
Since the Aces aren't counted, we don't need to rebalance the tags after we remove an Ace (read the website above). For Ace-reckoned counts, it becomes a bit more complicated, but easily do-able.
The equation from the website requires the sum of squared tags (y) for the entire shoe, which yields y = 127 * 0 + 128 * (1)^2 + 128 * (-1)^2 = 256. So we have TC * (+/- 1) * 383/256 for each card. This would be different if the tags had to be rebalanced.
We can then combine all the EV's to determine the overall insurance EV at a given count:
EV =
-1/4 + <-- Off the top
3/188 * 47/383 + <-- Dealer's Ace upcard
127 * TC * 0 + <-- 2,7,8,A are 0 since they aren't rebalanced
128 * TC * 383/256 * 3/188 * 47/383 + <-- 3 through 6
32 * TC * -383/256 * 3/188 * 47/383 + <-- 9
96 * TC * -383/256 * -9/188 * 47/383 <-- Faces
Simplifying:
EV = 9/8 * TC - 95/383
Setting EV to 0, we get:
9/8 * TC = 95/383
TC = 760 / 3447
Then, we use the equation in the website above to get the index:
Index = (760 / 3447 - 1/383) * 48 = 12061/1149 = 10.46
So when the TC > +11, take insurance.