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November 7th, 2011, 08:28 PM
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Senior Member
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Join Date: Jul 2010
Posts: 425
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The insurance puzzle
Anyone want insurance?
The real question is, how good of an insurance policy do I want?
1. HiLo, insurance correlation of 0.76
2. Balanced Zen, IC = 0.85
3. "Perfect" insurance count, IC = ?
4. Playing with info, IC = 1.0
What is the IC of #3?
What does IC really mean in terms of % EV gain from #1 to 2, 3, and #4?
How does SD, DD, 6D, and 8D affect these?
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November 7th, 2011, 10:52 PM
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Senior Member
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Join Date: Jan 2010
Posts: 295
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November 8th, 2011, 06:29 AM
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Executive Member
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Join Date: Mar 2011
Posts: 2,277
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Quote:
Originally Posted by flyingwind
Anyone want insurance?
The real question is, how good of an insurance policy do I want?
1. HiLo, insurance correlation of 0.76
2. Balanced Zen, IC = 0.85
3. "Perfect" insurance count, IC = ?
4. Playing with info, IC = 1.0
What is the IC of #3?
What does IC really mean in terms of % EV gain from #1 to 2, 3, and #4?
How does SD, DD, 6D, and 8D affect these?
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That's Ten value cards -9 all other cards +4. IC of 1.0 or perfect. Take insurance at TC +16 if I remember right.
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November 8th, 2011, 08:14 AM
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Member
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Join Date: Sep 2010
Posts: 42
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Here's an even simpler "perfect insurance count":
Tens are -2; everything else is +1.
IRC = -4 multiplied by the number of decks
Insure when the count is positive; don't when it's negative (at zero it's break-even)
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November 10th, 2011, 08:26 PM
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Member
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Join Date: May 2011
Posts: 19
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I found this somewhere.
"true counted" unbalanced insurance count,
IRC(initial running count) = -4*(number of decks)
count tag for non-tens are +1
count tag for tens are -2
when 6 deck, total 312 cards.
C : number of cards dealt
N: number of non-ten cards dealt
T: number of ten cards dealt
number of cards in shoe = 312-C
number of decks in shoe = (312-C)/52
RC = -24+N-2T
N+T = C
probability of insurance win = P
after some calc,
TC=52*(-24+C-3T)/(312-C)
then (52+TC)/156=
by computation,
=(96-T)/(312-C)
this is equal to density of ten cards in shoe =P
Kelly optimal insurance bet = BR*(3P-1)/2=
by computation,
=BR*TC/104
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November 10th, 2011, 09:34 PM
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Senior Member
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Join Date: Aug 2011
Location: Midwest
Posts: 108
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Quote:
Originally Posted by Mersenne Twister
I found this somewhere.
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Like the post immediately before yours?
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November 10th, 2011, 11:07 PM
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Member
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Join Date: May 2011
Posts: 19
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Quote:
Originally Posted by NAP
Like the post immediately before yours? 
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My interest in that insurance counting system is,
simulation result of using 2 counting systems, that is,
(in shoe game), high BC system (Hi-Lo, EBJ2, Wong Halves...) for
betting and playing, and that insurance count system for
determining insurance buying amount.
Someone can sim?
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November 16th, 2011, 08:49 PM
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Member
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Join Date: Aug 2011
Posts: 38
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Quote:
Originally Posted by Mersenne Twister
My interest in that insurance counting system is,
simulation result of using 2 counting systems, that is,
(in shoe game), high BC system (Hi-Lo, EBJ2, Wong Halves...) for
betting and playing, and that insurance count system for
determining insurance buying amount.
Someone can sim?
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You'd have to be counting with two different sets of card tags. You gonna keep track of all that? Like 8 and 9 will be neutral with your Hi-Lo, but you'll count them as +1 with your insurance count? Good luck!
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November 17th, 2011, 07:43 AM
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Member
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Join Date: May 2011
Posts: 19
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How about 2-man-team at same table?
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November 17th, 2011, 11:17 AM
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Senior Member
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Join Date: Aug 2011
Location: Midwest
Posts: 108
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Quote:
Originally Posted by Mersenne Twister
How about 2-man-team at same table?
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Now you're talking.
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