Simulate this count please!

[positiveEV]

2 = +4
3 = +5
4 = +6
5 = +8
6 = +5
7 = +3

Ignore 8

9 = -2
10,J,Q,K = -5
A = -6

Can anyone simulate it on 6-8 decks to see if it's good? I just made that by looking at the advantage and disadvantage of removing a card and then I rounded it at +/- 0.1%, so for each True Count of 10, this count should give you an advantage of 1%.

Thanks in advance :D

[Canceler]

You know this count is unbalanced, right? I'm not sure how True Count would work with an unbalanced count. Or would you like to provide the initial running count for 6D?

[positiveEV]

I know it's unbalanced, but it ends up with +3 and since there is 4x each card it can't make any whole number to end up there and I didn't wanted to add fractions. I just went on http://wizardofodds.com/blackjack/appendix7.html and I rounded the percentages and converted it into a count.

[QFIT]

This is very close to the Griffin 7 Count: 4, 4, 5, 7, 5, 3, 0, -2, -5. BC is a tiny bit higher, PE and IC are a tiny bit lower. There is only a tiny difference between these and UstonSS, a three-level count.

Originally Posted by asiafever

2 = +4
3 = +5
4 = +6
5 = +8
6 = +5
7 = +3

Ignore 8

9 = -2
10,J,Q,K = -5
A = -6

Can anyone simulate it on 6-8 decks to see if it's good? I just made that by looking at the advantage and disadvantage of removing a card and then I rounded it at +/- 0.1%, so for each True Count of 10, this count should give you an advantage of 1%.

Thanks in advance :D