New to the Forum and also to the game...browsed the web and this site appears to be the place to go to find answers for your questions. I tried this last week, well before I had ever heard the word Martingale or "progressive betting", and it appears I haven't made any great discovery. But, I did exactly what is described below last week at a Horseshoe Casino on the Missouri River between Omaha, NE and Council Bluffs, IA for a period of four days. I understand the whole "double betting" systems is said to have not work in the long run due to the streaks in which you lose the unthinkable ten plus times in a row, and also 1.) The amount of bankroll you need to back it up and 2.) The maximum limits at the tables. I guess what I did last week is exactly what everyone discusses except one variation.
I know there are some experts on this site, and I am asking for any help regarding advice on the situation below.
I played an average of six hours a day for 4 straight days, Tues-Fri. I averaged approx $300 in profit every 2 hours and walked away Friday afternoon with $3780 in pure profit. This is what I did, but how many times can I pull this off? What are the odds? Please help....
This is how I played:
Table rules that applied - $5 Min / $5000 Max
- I walked into the casino knowing ahead of time that I would need enough money to back my theory up in order to truly see if it worked.
- I planned to bet the min $5, then if lost continue to bet the 10, 20, 40, 80, 160, 320, 640, 1280, and 2560. I had the backing financially to do this and follow thru till the end. As you can see, with the table rules of the $5000 max, this strategy above would allow me lose 9 consecutive times as long as I won the 10th (a $2560 bet).
Due to the fact that I am still learning to play smarter and am not very good at card counting yet, I wanted to try out a betting strategy approach. But as I was thinking of what I wanted to do, this thought occured to me. I had a better chance if I didn't rely on my playing ability, but rather counted on the chance that a Dealer wouldn't go 10 consecutive hands without busting.
These are the rules that I abided by:
-Never hit on 12 or above, ever. That eliminated the option of busting.
-Never double down, split, etc.
-Play $5 Min, if lost double to $10, then to $20, and so on....meaning every winning hand gave me exactly a $5 profit each and every time.
Basically I was a winner as long as the Dealer didn't go 10 consecutive hands without busting above 21.
In four days of playing the most hands a dealer went in a row without busting was 7, and she busted on the 8th. I had $640 on the table and I won my $5 profit. This allowed me to walk with almost four large by the time Friday rolled around, all on winning $5 hands based on the principle the Dealer wasn't going to deal 10 consecutive hands and never bust.
If anyone has any input on this please speak up. What are the odds that the Dealer would go 10 hands without busting once? Does anyone have any idea?
I know this sounds like the Martingale, but I'm basing my theory soley on the idea of the Dealer going 10 hands, not on my playing ability, since I myself will NEVER bust using the set rules.
I understand that at some point you would eventually take an approx $5000 loss and lose ten in a row, but wouldn't it be well less than the profits I am going to make weekly?
Also, the 11th hand would require a bet of $5120, just a bit over the max, but would also mean you can really allow yourself another shot on the 11th try since $5120 isn't far off from the table Max. Figure the odds of that.
I look forward to your community's advice. Thank you.
I know there are some experts on this site, and I am asking for any help regarding advice on the situation below.
I played an average of six hours a day for 4 straight days, Tues-Fri. I averaged approx $300 in profit every 2 hours and walked away Friday afternoon with $3780 in pure profit. This is what I did, but how many times can I pull this off? What are the odds? Please help....
This is how I played:
Table rules that applied - $5 Min / $5000 Max
- I walked into the casino knowing ahead of time that I would need enough money to back my theory up in order to truly see if it worked.
- I planned to bet the min $5, then if lost continue to bet the 10, 20, 40, 80, 160, 320, 640, 1280, and 2560. I had the backing financially to do this and follow thru till the end. As you can see, with the table rules of the $5000 max, this strategy above would allow me lose 9 consecutive times as long as I won the 10th (a $2560 bet).
Due to the fact that I am still learning to play smarter and am not very good at card counting yet, I wanted to try out a betting strategy approach. But as I was thinking of what I wanted to do, this thought occured to me. I had a better chance if I didn't rely on my playing ability, but rather counted on the chance that a Dealer wouldn't go 10 consecutive hands without busting.
These are the rules that I abided by:
-Never hit on 12 or above, ever. That eliminated the option of busting.
-Never double down, split, etc.
-Play $5 Min, if lost double to $10, then to $20, and so on....meaning every winning hand gave me exactly a $5 profit each and every time.
Basically I was a winner as long as the Dealer didn't go 10 consecutive hands without busting above 21.
In four days of playing the most hands a dealer went in a row without busting was 7, and she busted on the 8th. I had $640 on the table and I won my $5 profit. This allowed me to walk with almost four large by the time Friday rolled around, all on winning $5 hands based on the principle the Dealer wasn't going to deal 10 consecutive hands and never bust.
If anyone has any input on this please speak up. What are the odds that the Dealer would go 10 hands without busting once? Does anyone have any idea?
I know this sounds like the Martingale, but I'm basing my theory soley on the idea of the Dealer going 10 hands, not on my playing ability, since I myself will NEVER bust using the set rules.
I understand that at some point you would eventually take an approx $5000 loss and lose ten in a row, but wouldn't it be well less than the profits I am going to make weekly?
Also, the 11th hand would require a bet of $5120, just a bit over the max, but would also mean you can really allow yourself another shot on the 11th try since $5120 isn't far off from the table Max. Figure the odds of that.
I look forward to your community's advice. Thank you.
