Math problem?

[jack,jackson]

1. Key in the first three digits of your phone number (NOT the Area code...)
2. Multiply by 80
3. Add 1
4. Multiply by 250
5. Add to this the last 4 digits of your phone number
6. Add to this the last 4 digits of your phone number again.
7. Subtract 250
8. Divide number by 2

Whats the answer????

[Sonny]

SPOILER WARNING!!!

Solution is below in invisible ink...

N=((80x+1)*250+2y-250)/2
=(20,000x+250+2y-250)/2
=(20,000x+2y)/2
=10,000x+y
=First 3 digits * 10,000 + Last 4 digits

e.g.
123-4567
123 * 10,000 + 4567 = 1,234,567


-Sonny-

[Canceler]

Originally Posted by jack,jackson

Whats the answer????

It's my birthday!!! No, wait...

[jack,jackson]

Originally Posted by Sonny

SPOILER WARNING!!!

Solution is below in invisible ink...

N=((80x+1)*250+2y-250)/2
=(20,000x+250+2y-250)/2
=(20,000x+2y)/2
=10,000x+y
=First 3 digits * 10,000 + Last 4 digits

e.g.
123-4567
123 * 10,000 + 4567 = 1,234,567


-Sonny-

Very good sonny!!!

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[SilentBob420BMFJ]

i got my phone number! awsome.. if you didnt get your phone number, you forgot to hit the = key after adding, as 10+1*2 is NOT 22