Can someone explain to me mathematically that why when player has a hard hand 9, the strategy calls for double down when dealer's up card is 3-6; When player has a soft-hand 9(A, 8), the strategy calls for stand when the dealer's up card is 3-5, double down only on 6? By the same token, why player has hard 10 total, the strategy calls for double down when dealer has 2-9, but in soft hand 10(A,9), the strategy calls for stand?
blackjack strategy?
- Thread starter ricardo
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Sure, but only if you know what the terms "combinatorial analysis" and "expected value" mean.
Sure, but only if you know what the terms "combinatorial analysis" and "expected value" mean.
Only in high school level
Can't get any more mathematical than THIS. :grin:
Well said, but what about hard hand vs. soft hand 9?
Your question is akin to
Why do we hit 14vT but stand on 19 v 4?
They're two different hands.
A8 is very different from 54.
One is a 9/19, the other is a 9.
You can't hurt the 9 by hitting. It's impossible to end up with a hand that you'd rather have stayed with.
With the soft 19, there are only 2 cards that improve your hand, 4 that keep it the same, and 7 that weaken it. So you are only going to double in very favorable circumstances (v6 in a H17 game, or with a high count).