OBB, OBBO, BB+1, do you know the differences?

#1
From wiki:

* BB+1 (Busted Bets plus one): After removing from the table all busted bets, all winnings and original bets from hands totaling "21", and all original bets from forfeited hands, the player loses just one bet, even if he has multiple split hands in the one box.

* OBBO (Original Bets and Busted Only): After removing from the table all busted bets, all winnings and original bets from hands totaling "21", and all original bets from forfeited hands, the player loses just one bet from each split hand remaining. If he has not split, he loses just one bet.

In summary, BB+1 is a loss of one bet per box, and OBBO is a loss of one bet per hand, given that busted bets, winnings, and original bets from forfeits and winning hands have been removed from the table. BB+1 is the more common of the two rules; the only casinos that have OBBO are Burswood Casino in Perth, and Casino de Genting, Malaysia.

Can anyone explain each one in simple english? Still a little confused
 
#2
You play 1 box and bet $10.
If you split 3 times, you have now 4 hands.

Assume no bust:

In BB+1, you will lose exactly $10 to dealer BJ. Regardless how many times you doubled or split.

In OBBO, you will lose exactly $10 per hand you have. Regardless how many times you have doubled. Obviously the more you have split, the more hand you have, therefore you will lose more.


With bust, I don't how to explain simply.

Basically you lose the busted hand. Then the dealer look at your hand and pretend the busted hand does not exist and applied the no-bust logic above.

For example:

1) You sit down and play
2) You play against dealer A until you have played all your hands.
3) dealer A has a heart attack and dies.
4) dealer B start dealing cards to the dealer box and gets a BJ. Dealer B doesn't care if at step 2 you have busted any hands.
 
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