9/5 Blackjack House Edge?

S

Safehouse

Member
#1
#1
BetUS has a promotion on Thursdays where a Blackjack pays 9/5, instead of 3/2 or the dreaded 6/5. I've looked and can't find any information on what this does to the house edge. I know that 6/5 increases the house edge on average from 0.45% to 1.82%.

As 9/5 is better than 3/2, does anyone know how to compute the improved edge?
 
gronbog

gronbog

Well-Known Member
#2
#2
As a very rough calculation, you get a blackjack about once every 21 rounds. So you will be paid an extra 9/5 - 3/2 = 0.3 units once every 21 hands. The extra player edge is therefore 0.3/21 = 0.0143 = 1.43% which is quite substantial. It is enough to provide a positive advantage off the top for a typical game.

As an exercise, use the same method to show that this promotion improves the player advantage by the same amount that 6/5 degrades it.
 
M

Midwest Player

Well-Known Member
#4
#4
gronbog said:
As a very rough calculation, you get a blackjack about once every 21 rounds. So you will be paid an extra 9/5 - 3/2 = 0.3 units once every 21 hands. The extra player edge is therefore 0.3/21 = 0.0143 = 1.43% which is quite substantial. It is enough to provide a positive advantage off the top for a typical game.

As an exercise, use the same method to show that this promotion improves the player advantage by the same amount that 6/5 degrades it.
Click to expand...
Okay, why the difference? G Man posted on Norm's site the additional edge is 1.36%
 
The G Man

The G Man

Well-Known Member
#5
#5
The difference comes from the fact that you have to account for those times when the Dealer also have a Blackjack and you only get a push on the hand.
 
gronbog

gronbog

Well-Known Member
#6
#6
The difference is that I used (and said) a very rough calculation using one blackjack every 21 hands. It is, of course, not exactly one every 21 hands and as G Man has pointed out, I did not account for pushes.
 
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