Kelly Criteria: IS this full or half
- Thread starter PokerJunky
- Start date
That's actually more than full Kelly. For full Kelly, you'd need to divide that amount by the variance, which is roughly 1.1 or 1.2.
I haven't checked the .515 figure you used, but I assume that is the change in edge per true count point, and it looks about right for that purpose.
I've always just rounded to 0.5.
I haven't checked the .515 figure you used, but I assume that is the change in edge per true count point, and it looks about right for that purpose.
I've always just rounded to 0.5.
Thanks Ken
For example, for a game w/ the following rules (6 Decks, S17, DA2, DAS, OBO, No surrender) the house has a .44% advantage. Therefore if the TC is +3 and a bankroll of $5000 the max bet would be
My method:
[-.44% + (.515*3)] = 1.105% of $5000 or $55.25 (full Kelly) or $26.73 (half Kelly)
Your method
[-.44% + (.5*3)]/1.2 = 0.883% of $5000 or $44.16 (full Kelly) or $22.08 (half Kelly)
I'm I right? Thanks again for the help.
For example, for a game w/ the following rules (6 Decks, S17, DA2, DAS, OBO, No surrender) the house has a .44% advantage. Therefore if the TC is +3 and a bankroll of $5000 the max bet would be
My method:
[-.44% + (.515*3)] = 1.105% of $5000 or $55.25 (full Kelly) or $26.73 (half Kelly)
Your method
[-.44% + (.5*3)]/1.2 = 0.883% of $5000 or $44.16 (full Kelly) or $22.08 (half Kelly)
I'm I right? Thanks again for the help.