True Count probability?

curtdbz

New Member
Is there a way to convert the True Count to the probability of beating the dealer in percent? Or is that not even possible?
 

FLASH1296

Well-Known Member
The probability of your winning the upcoming hand is about 43% "off-the top".

It really does NOT change much at all, especially if you know your indexed plays at negative True Counts.

So the question is all but moot for any purpose that I can think of.
 
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