curtdbz New Member May 27, 2009 #1 Is there a way to convert the True Count to the probability of beating the dealer in percent? Or is that not even possible?
Is there a way to convert the True Count to the probability of beating the dealer in percent? Or is that not even possible?
FLASH1296 Well-Known Member May 27, 2009 #3 The probability of your winning the upcoming hand is about 43% "off-the top". It really does NOT change much at all, especially if you know your indexed plays at negative True Counts. So the question is all but moot for any purpose that I can think of.
The probability of your winning the upcoming hand is about 43% "off-the top". It really does NOT change much at all, especially if you know your indexed plays at negative True Counts. So the question is all but moot for any purpose that I can think of.
C callipygian Well-Known Member May 27, 2009 #4 rukus said: does it matter? it'll be below 50% even at high TCs. Click to expand... Not if you're at TC +17.
rukus said: does it matter? it'll be below 50% even at high TCs. Click to expand... Not if you're at TC +17.
QFIT Well-Known Member May 27, 2009 #5 curtdbz said: Is there a way to convert the True Count to the probability of beating the dealer in percent? Or is that not even possible? Click to expand... See http://www.blackjackincolor.com/truecount5.htm
curtdbz said: Is there a way to convert the True Count to the probability of beating the dealer in percent? Or is that not even possible? Click to expand... See http://www.blackjackincolor.com/truecount5.htm
X Xenophon Well-Known Member May 27, 2009 #6 QFIT said: See http://www.blackjackincolor.com/truecount5.htm Click to expand... Outstanding material.
QFIT said: See http://www.blackjackincolor.com/truecount5.htm Click to expand... Outstanding material.