then i think u don't agree with my strategy then
becuz... if we play NEVER BUST strategy.... that means we'll never bust right?
and if the dealer bust... we'll be 7times our initial bet....
we're using the same deck so that means we have the same pourcentage of winning..
if dealer stops at 17 .. it doesn't mean that he'll win all my 7 hands.... either 18,19,20, or even 21....
but once he bust... we'll win 7 hands...
so as i've tried.. it was..
1 st game + 7 ( dealer bust )
2 nd game + 4 ( win 2 lose 5 )
3 rd game + 5 ( win 4 lose 3 )
4 th game + 10.5 ( win 6 with Blackjack and lose one )
and so on....
i know that u don't agree with me.. but .. just wanna make sure..
cuz i've tried with 7 decks... and always the same way of playing....
becuz... if we play NEVER BUST strategy.... that means we'll never bust right?
we're using the same deck so that means we have the same pourcentage of winning..
if dealer stops at 17 .. it doesn't mean that he'll win all my 7 hands.... either 18,19,20, or even 21....but once he bust... we'll win 7 hands...
If you play ONE hand of $10 and win $70 dollars, that's 7 times your money. If you play 7 hands of $10 dollars and win $70, that's EVEN money
What I'm saying is when you play 7 hands and win 7 hands, you have won EVEN money not 7 times your original bet......i don't really understand what you trying to say... ? ^^
what do u mean by .. If i pay one hand of 10$ and win 70$ ( how can i win 70$ when i'm only playing 10$ )
what i'm trying to say is .. always play with the same amount of money without raise or decrease... ... always take when it's below 12... no matter what dealer has .... once i get over 11 ... then i stop.. ( never bust strategy )
so that means .. IF DEALER bust... ( without any exception ) bank has to PAY every hand ... but if dealer doesn't bust ... maybe he can get 17, 18, 19, 20 or even 21...... it doesn't mean all my 7 hands are LOSING... so in a long run.. i will win...? BUT I NEED MORE CALCULATION ( since it's ALL MATH ) need STATs professional
What I'm saying is when you play 7 hands and win 7 hands, you have won EVEN money not 7 times your original bet......
Never bust: For my analysis of this strategy I assumed the player would never hit a hard 12 or more and based all other decisions on maximizing expected value under this assumption. This results in a house edge of 3.91%.
i don't really understand what you trying to say... ? ^^
what do u mean by .. If i pay one hand of 10$ and win 70$ ( how can i win 70$ when i'm only playing 10$ )
Anybody played 7 decks at a casino?
... deal bust's percentage is 100% more than me ~
me bust = 0%
That's not true at all. The dealer will not bust 100% of the time. They will probably only bust about 30% of the time. That means you will be losing some money 70% of the time. Does that still sound like a good plan?
-Sonny-
i mean... i will never bust... however .. the Bank will ~... if he bust then.. i win..
but even tho he doesn't bust... it doesn't mean that i will lose .. right??