If the count calls for both a surrender and insurance, what do you do?
For example, I have 14 vs Ace, and the true count is 5, do I surrender or take insurance?
Actually, could you take insurance, and if the dealer checks and does not have blackjack, could you then surrender?
Yes, but it's kind of obvious to an astute PB that you're using your brain.Actually, could you take insurance, and if the dealer checks and does not have blackjack, could you then surrender?
An astute pit boss will figure out you're using your brain no matter what if you're counting cards. I personally am not going to discard powerful tools like surrender and insurance because that one play will make or break my longevity!Yes, but it's kind of obvious to an astute PB that you're using your brain.
An astute pit boss will figure out you're using your brain no matter what if you're counting cards. I personally am not going to discard powerful tools like surrender and insurance because that one play will make or break my longevity!
Spreading your bets with the count will make it obvious to an astute pit boss you're smart. Should we stop doing that?
Best play, insure then surrender only after the insurance bet wins half the time or more, before that threshold surrender without insuring.
I cannot follow you here. The break-even point for insurance is 1/3, not 1/2. Unless your intention is risk-averse play (which is a legit question in this situation), the pure EV-best play is to insure whenever insurance is favourable, and to surrender whenever surrender is favourable. If both are favourable, do both (assuming late surrender).
The outcome of the insurance bet has no influence on your surrender bet, as you are offered late-surrender only when the dealer doesn't have blackjack. Likewise, you can late-surrender whether or not you placed the insurance bet. From the pure EV standpoint, there is no reason to not insure your hand when 1/3 < pDBJ < 1/2. But maybe I just get you wrong.
Yes, but it's kind of obvious to an astute PB that you're using your brain.Actually, could you take insurance, and if the dealer checks and does not have blackjack, could you then surrender?
If the count calls for both a surrender and insurance, what do you do?
For example, I have 14 vs Ace, and the true count is 5, do I surrender or take insurance?
With that, I fully agree. If you play insurance/surrender, your EV before peeking for BJ is -2/3.Let me try again.
You can simply surrender your hand for an EV of -.5 and be done with it. At your insurance index let us assume insurance is a break even proposition. That means you win one third of the time and lose 2/3 of the time an EV of 0, 1/3 you win 1 while 2/3 you lose .5 of your bet. That means your total play for the hand in aggregate is 1/3*(2*.5 - 1) (your outcome if you win your insurance bet minus the loss of your main bet that happens at the same time) + 2/3*(-.5 + -.5) (the insurance loss plus the surrender loss).
Are we talking about late surrender ? Because then you cannot surrender before the dealer peeks for BJ. If you don't plan to play insurance, your EV before peek is still the sameThis sum is -2/3 which is less -1/2 which is surrender on its own.
With that, I fully agree. If you play insurance/surrender, your EV before peeking for BJ is -2/3.
Are we talking about late surrender ? Because then you cannot surrender before the dealer peeks for BJ. If you don't plan to play insurance, your EV before peek is still the same
1/3 * (-1) + 2/3 * (-.5) = -2/3
as insurance was a zero-EV sidebet not influencing your hand.
If you were talking about early surrender, then I must apologize, EV of early surrender is indeed always -1/2. But it is no secret that early surrender is more favourable (by 1/3 * .5 = 1/6 in this scenario) than late surrender.
But even with early surrender, there is no difference in taking / not taking insurance (besides variance).