ArcticInferno
Well-Known Member
Is there a difference between playing two hands of $25 versus one hand of $50?
Supposedly, there's no difference in the long run (expected value).
However, I read that playing two hands will reduce fluctuations (standard deviation).
A more efficient approach would be to play two hands during positive counts and
play one hand during negative counts. But constantly switching between one hand
and two hands irritates other players, and the dealer (and the pit) will scrutinize you.
Playing two hands of $25 is like playing at the $50 minimum table. But since I'm
playing two hands, the fluctuation will be lower than playing one hand of $50.
If the count plummets hopelessly, then of course I would Wong out.
Is my analysis correct?
Supposedly, there's no difference in the long run (expected value).
However, I read that playing two hands will reduce fluctuations (standard deviation).
A more efficient approach would be to play two hands during positive counts and
play one hand during negative counts. But constantly switching between one hand
and two hands irritates other players, and the dealer (and the pit) will scrutinize you.
Playing two hands of $25 is like playing at the $50 minimum table. But since I'm
playing two hands, the fluctuation will be lower than playing one hand of $50.
If the count plummets hopelessly, then of course I would Wong out.
Is my analysis correct?