mickpk said:As safe as any of the math I have produced here.
You couldn't even correctly calculate the house edge in your invented example!
mickpk said:As safe as any of the math I have produced here.
Supercoolmancool 1 Mickpk 0. Just kidding Mickpk. lol
agree that you PROBABLY will, but you never EXPECT to win any of your bets.
I don't know how much math mickpk really knows, but a roullette game with 100 reds, 100 blacks, and 1 zero does not yield a house edge of exactly .5%. The house edge is really 1/201, or .4975%.
Thanks for making Scott's personal and private
e-mails, of which were SOLELY addressed to you, a topic of fanfare
and merriment.
assuming no house edge (a decent assumption considering you're only making 2 bets here)
That is why I specifially asked Mickpk if he thought that a .5% house edge was a 50/50 game.
Using your own system of math with the added twist of the ACTUAL expected win %,
7200*0.0263 = $189.36 (the total amount lost to roulette)
If 4800 is the WR after the roulette bets for each account than the total WR for all accounts is:
4800*36 = 172800 (the total WR for all accounts)
172800*0.005 = $864.00 (the total amount lost to BJ)
Tell me, how are you continuing to wager the $4800 on the loser Black bet with $0 in the account? You can't, therefore that wagering has to be removed from your equation because that WR has effectively been completed. Thus your total wagers are only on the Red winners, balance of WR is 4800*18 = 86400*0.005 = 432
194.40+432 = $626.40.
Hot dang. I know what Scott and my problem is. We have been assuming all along a house edge. Now it makes sense. Now we are talking. The only problem is that roulette has a 2.7% house edge 5.4 times greater than blackjack, but after you eliminate that then you have to overcome the opstacle of betting 2 accounts on the same spin of the wheel. An impossible feet. But we will just pretend those don't exist.
That is why I specifially asked Mickpk if he thought that a .5% house edge was a 50/50 game.
mickpk said:With that philosophy, card counting fails as well.