question regarding sd cc

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Thunder

Well-Known Member
This may sound like a silly question but If you're playing at a table at a SD game with 4 other players and the TC is +1, is that really enough to justify betting more knowing full well that the TC could drop down to -4 by the time you get your cards? At least in multiple decks you know the running count is much higher so there are more 10/s aces available. I can understand it not being a big issue when you're heads up against the dealer but with other players at the table, I think you run the risk of having the good cards eaten up.
 
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stophon

Well-Known Member
Actually, I think your advantage would be lower when playing at third base verses first base in this case (tho maybe not by enough to really matter).

Reason being is that odds are you will be playing with a lower count by the time you are dealt your cards.

Edit:
here's some quick math
i assumed only two players for simplicity's sake, hi-lo count
let's say 5 low cards have been played, 4 high cards and 3 neutral cards
The RC is +1 and the TC is 1.3 and player adv has increased by about 65%
(20-5)=15 low cards left
(20-4)=16 high cards left
(12-3)=9 neutral cards left
P(count will be +2) = 15/40 * 1.3333% (increase in player adv)
P(count will be 0) = 16/40 * 0%
P(count will be +1) = 9/40 * .66667%
E.V. = 65%

Haha, I'm wrong. Your advantage is the exact same. The increased penetration cancels out the increased likelihood of the count going down.
 
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bj bob

bj bob

Well-Known Member
Forget it

Thunder said:
This may sound like a silly question but If you're playing at a table at a SD game with 4 other players and the TC is +1, is that really enough to justify betting more knowing full well that the TC could drop down to -4 by the time you get your cards? At least in multiple decks you know the running count is much higher so there are more 10/s aces available. I can understand it not being a big issue when you're heads up against the dealer but with other players at the table, I think you run the risk of having the good cards eaten up.
Click to expand...
If you intend to play single deck as an AP you have no business playing at a full or even nearly full table. Heads up or one other player is the only way to go for several reasons. RoX, as Sonny indicated is one of the major reasons. I'd love to have a buck for every SD table I've passed up because of 2 or more people at the table. I don't have much tolerance for tables filling up after I've sat down, maybe one or two decks is my limit, especially if my drink has already been ordered. After that, I'm outta there.
 
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R

rukus

Well-Known Member
stophon said:
Actually, I think your advantage would be lower when playing at third base verses first base in this case (tho maybe not by enough to really matter).

Reason being is that odds are you will be playing with a lower count by the time you are dealt your cards.

Edit:
here's some quick math
i assumed only two players for simplicity's sake, hi-lo count
let's say 5 low cards have been played, 4 high cards and 3 neutral cards
The RC is +1 and the TC is 1.3 and player adv has increased by about 65%
(20-5)=15 low cards left
(20-4)=16 high cards left
(12-3)=9 neutral cards left
P(count will be +2) = 15/40 * 1.3333% (increase in player adv)
P(count will be 0) = 16/40 * 0%
P(count will be +1) = 9/40 * .66667%
E.V. = 65%

Haha, I'm wrong. Your advantage is the exact same. The increased penetration cancels out the increased likelihood of the count going down.
Click to expand...
i hope this clears up your thoughts/comments in iCountNTrack's sticky thread :).

i posted it there but might as well include it here for good measure for the OP:
http://www.bjmath.com/bjmath/counting/tcproof.htm (Archive copy)
 
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