The house edge for the rules of Coral, Willhill, Expect, VC, and I think Bluesquare (live dealer online casinos) for 8 decks, is 0.65%. However for one deck the house edge is only 0.11%. (I calculated this from the calculator:
http://www.beatingbonuses.com/bjstrategy.php?decks=8&soft17=stand&doubleon=any2cards&peek=off&surrender=no&opt=2&btn=Calculate
The dealer peeks for blackjack when he has an ace though, so the house edge is slightly less)
Now, I got a figure that the player's edge increases by 0.496% when the true count increases by one unit (e.g. from 0 to +1, from +1 to +2, and so on). I dont remember where I got this from, and I guess it differs depending on the rules. But supposing it applies for these rules too, then to overcome the house edge when the decks left are 8, you need a true count of 0.65/0.496=1.386, which is a running count of 1.386x8=11.088. When the decks left are 6, the house edge is 0.63%, so to overcome the house edge you need a true count of 0.63/0.496=1.344 which is a running count of 1.344x6=8.064. When the decks left are 4, the house edge is 0.58%, so to overcome the house edge you need a true count of 0.58/0.496=1.237 which is a running count of 1.237x4=4.948.
The thing is, I doubt these calculations. I've got a sense that the running counts to overcome house edge are lower than the above values. Anybody can help me? Online articles I would appriciate. Give me your simulation/calculator results for 8, 6, and 4 decks left. But I want to know the exact theory which gives the answer, as it seems that the running count which overcomes house edge is NOT simply a given true count (which applies for the 1 deck house edge) multiplied by the number of decks left. The TRUE count to overcome house edge seems to differ depending on the number of decks left, and is not always the same (besides, this is also the case regarding insurance).
http://www.beatingbonuses.com/bjstrategy.php?decks=8&soft17=stand&doubleon=any2cards&peek=off&surrender=no&opt=2&btn=Calculate
The dealer peeks for blackjack when he has an ace though, so the house edge is slightly less)
Now, I got a figure that the player's edge increases by 0.496% when the true count increases by one unit (e.g. from 0 to +1, from +1 to +2, and so on). I dont remember where I got this from, and I guess it differs depending on the rules. But supposing it applies for these rules too, then to overcome the house edge when the decks left are 8, you need a true count of 0.65/0.496=1.386, which is a running count of 1.386x8=11.088. When the decks left are 6, the house edge is 0.63%, so to overcome the house edge you need a true count of 0.63/0.496=1.344 which is a running count of 1.344x6=8.064. When the decks left are 4, the house edge is 0.58%, so to overcome the house edge you need a true count of 0.58/0.496=1.237 which is a running count of 1.237x4=4.948.
The thing is, I doubt these calculations. I've got a sense that the running counts to overcome house edge are lower than the above values. Anybody can help me? Online articles I would appriciate. Give me your simulation/calculator results for 8, 6, and 4 decks left. But I want to know the exact theory which gives the answer, as it seems that the running count which overcomes house edge is NOT simply a given true count (which applies for the 1 deck house edge) multiplied by the number of decks left. The TRUE count to overcome house edge seems to differ depending on the number of decks left, and is not always the same (besides, this is also the case regarding insurance).
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