So, Ive been thinking againand was just wondering, if anybody knew, if they thought this new different kind of count, could break the .70 pe, barrier,(single parameter counts) regardless of the work and effort. It does work, but I dont know how crude or effective, it would be.
The count:
2,3,4,5=100's
6,7,8,9=10's
T,J,Q,K=1's
Example:
A)3,5=200
B)X,X=202
C)7,8=222(000)
In example C, with a little practice, the middle cards, would just cancel the small cards and facecards out.
Example2:RC/000
A)2,X,X=102
B)3,5,X=303
C)6,8=101
In example B, can you possibly see why 13v2, would be a good hit?
______________________________________________________________
I tried this with 1 deck of cards and ended on Zero on my first counting attempt. Also not 1 of my 3 subgroups(low,med,high) went above 5.
Does anyone think, that, with using this method its possible to attain a .80 or .90 PE?
Also could doubling H12 or H13 be identified, mathematically correct?
Any feedback is welcome!![]()
how can u input multiple side counts into CVdata? I was just curious because i figured you could set all the tags at 0, and tag 2-5 as 1, then keep a grouped SC of 6-9 but how do you add the additional 10 side count?
thanks
So, Ive been thinking againand was just wondering, if anybody knew, if they thought this new different kind of count, could break the .70 pe, barrier,(single parameter counts) regardless of the work and effort. It does work, but I dont know how crude or effective, it would be.
The count:
2,3,4,5=100's
6,7,8,9=10's
T,J,Q,K=1's
Example:
A)3,5=200
B)X,X=202
C)7,8=222(000)
In example C, with a little practice, the middle cards, would just cancel the small cards and facecards out.
Example2:RC/000
A)2,X,X=102
B)3,5,X=303
C)6,8=101
In example B, can you possibly see why 13v2, would be a good hit?
______________________________________________________________
I tried this with 1 deck of cards and ended on Zero on my first counting attempt. Also not 1 of my 3 subgroups(low,med,high) went above 5.
Does anyone think, that, with using this method its possible to attain a .80 or .90 PE?
Also could doubling H12 or H13 be identified, mathematically correct?
Any feedback is welcome!![]()
for better you need use littlebit different count
2,3,4,+100 5+200
678+10 9+20
10,j,q,k,a+1
i try some 1 months ago but i stop becouse countis (0 ,110 ,14 )whot a you think about this?
The LIMITS of p.e. are discussed in Theory of Blackjack, and there are examples of the best counts.
I am sure that you are aware that P.E. is of minor importance in shoe games.