Here you go:aslan said:So what is the math to determine the odds of a streak of X or more occurring within Y number of hands (pushes don't break the streak)? Can I refer back to a previous post?
Thanks! Exactly what I was looking for.Sonny said:
I'm not sure it is, based on the wording of your question. I think the thread Sonny linked only explains one piece of what your question asks. You may want to reread my earlier posts in this thread. I think you are asking the same thing as the OP, just in a more general sense. If you are in fact asking the same thing as the OP, then the fact is that I don't know how to properly calculate the answer, I just know why the "usual" answer doesn't seem to be correct.aslan said:Thanks! Exactly what I was looking for.
Grasshopper said:Muppet, Nynefingers and Sonny.
Thanks for all the input on this. Read, and reread , the posts and watched the video.
I think I get the concept on the independence thing but a bit confusing. I will continue chewing on it.
I got the point on the calculation. Probability somewhere in the 1:1600 - 1:2500 bracket, probably toward the higher side.
That is enough of an answer to resolve my issues, at least as far as this question
Thanks for the education. Much appreciated.
which problem are you unsure of how to calculate the answer?Nynefingers said:I believe that is why the referenced website shows a lower probability of a particular losing streak within a given hand sample size. I don't know the math to calculate the correct odds given the dependence problem, so I would approach it with a simple simulation.
doesn't this equation correctly solve the "dependence problem"? or is there a different scenario that you are talking about in the first quote aboveNynefingers said:Close. What are the chances of at least one 10 hand losing streak within a sample of 2000 hands? It isn't 1991x=1.62=162%. The calculation you did gives us the expected number of 10 hand losing streaks in 30 hands. The chance of having a 10 hand losing streak in 30 hands would be
1-(1-x)^21 = 0.0170