Time of Play - $5 6:5 vs $10 3:2

bjhack

Well-Known Member
#1
Assuming BS, for an equal amount bet, a 3:2 table has it all over a 6:5 table. However, if you want to maximize time at tables instead of minimzing losses, and assuming the same rate of play, how much longer/shorter (hands would be a good measure) would you play placing a minimum bet at a $5 6:5 table as compared to a $10 3:2 table for the same loss? (This may be a question for the Wizard...)

Bruce
 
#5
bjhack said:
Assuming BS, for an equal amount bet, a 3:2 table has it all over a 6:5 table. However, if you want to maximize time at tables instead of minimzing losses, and assuming the same rate of play, how much longer/shorter (hands would be a good measure) would you play placing a minimum bet at a $5 6:5 table as compared to a $10 3:2 table for the same loss? (This may be a question for the Wizard...)

Bruce
It depends on the rules at both, but in most circumstances the $10 3:2 table would be a little better.
 

Sucker

Well-Known Member
#6
The house advantage for a BS player who's playing a 3:2 single deck game with typical rules (if you can even find one) is somewhere in the neighborhood of 0.2% (2/10 of 1%). This means that for every $10 bet that you make, you'll lose an average of 2 cents.

The house edge for the 6:5 game is about 1.6%. Every time you bet $5 you lose
8 cents.

Therefore, if you were playing a 3:2 game and betting $10, and your friend was playing a $5 game that payed 6:5; even though you were betting twice as much;you could expect to be able to play FOUR times as long as him, for the same amount of money.

This just serves to demonstrate how utterly HORRIBLE the 6:5 game actually IS.
Almost CRIMINAL!
 

shadroch

Well-Known Member
#7
Sucker said:
The house advantage for a BS player who's playing a 3:2 single deck game with typical rules (if you can even find one) is somewhere in the neighborhood of 0.2% (2/10 of 1%). This means that for every $10 bet that you make, you'll lose an average of 2 cents.

The house edge for the 6:5 game is about 1.6%. Every time you bet $5 you lose
8 cents.

Therefore, if you were playing a 3:2 game and betting $10, and your friend was playing a $5 game that payed 6:5; even though you were betting twice as much;you could expect to be able to play FOUR times as long as him, for the same amount of money.

This just serves to demonstrate how utterly HORRIBLE the 6:5 game actually IS.
Almost CRIMINAL!

While I agree with your math, don't you have to factor BR into the equation.
Suppose you only have a $50 to $100 BR. Shouldn't your risk of ruin come into play?
 
#8
Sucker

Sucker said:
The house advantage for a BS player who's playing a 3:2 single deck game with typical rules (if you can even find one) is somewhere in the neighborhood of 0.2% (2/10 of 1%). This means that for every $10 bet that you make, you'll lose an average of 2 cents.

The house edge for the 6:5 game is about 1.6%. Every time you bet $5 you lose
8 cents.

Therefore, if you were playing a 3:2 game and betting $10, and your friend was playing a $5 game that payed 6:5; even though you were betting twice as much;you could expect to be able to play FOUR times as long as him, for the same amount of money.

This just serves to demonstrate how utterly HORRIBLE the 6:5 game actually IS.
Almost CRIMINAL!
It is criminal, and what really pisses me off is they still take all the bets when the dealer has a BJ.:mad: And all those amazingly stupid players sitting there playing this game, which is now offered on shoes and csm's.

You would think people would put more value on their money, which most work very hard for.:confused::whip:

CP
 
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