As a basic strategy guy I usually surrender a pair of eights against the dealer's Ace, ten and nine and sometimes against the eight. I know surrendering against the ten, nine and eight goes against basic strategy rules but it seems more likely than not I would end up with a pair of hands with an 18 at best, costing four times as much, and probably losing both. Moreover, when splitting the eights I could end up busting both hands if I initially draw low cards, thereby losing four times as much money and not even having a hand to cash in on if the dealer ends up breaking. In addition, as you know surrendering allows you to get back 1/2 your bet. So if you are playing $10/hand and you surrender a pair of 8's...you only lose $5. If you split and lose both hands...you lose $20. If you split and double down.....you lose $40. Bear in mind I'm only talking about a pair of 8's against the dealer's Ace, ten, nine and eight. Just my own modification to basic strategy. I seem to have better sessions doing it. Does this sound reasonable or am I wrong? Thanks.